Wednesday, January 11, 2012

Maximum distance physics problem help?

I think you're missing the m of the motorcycle because you cant apply the friction coeficient without the weight of the object, once you have it it's pretty straight forward, you have to calculate the total amount of energy (kinetic + potential = ((.5*(m)*(14.7)^2)+((m)(9.81)(0)) ) of the motorcycle at point A ( as soon as it hits the ramp ) then osme of that energy will remain kinetic and some will transform into potential, to know how fast you're going at the very top you have to know how many energy you need to get there (m*9.81*2.10) then you substract it from the initial amount of energy, ((.5*(m)*(14.7)^2) - (m*9.81*2.10) ) once you have the remaining energy (let's call it Ea) you still have to calculate the work done by the friction, so you have your weight in the ramp and you have to break it down in Wx and Wy its simple, just multiply it like this ( W*cos 27�) then ( (W*cos 27�) * (.02) * ( (2.1/cos27�) ) ) and finally you have the amount of work done by the friction, just substract it from (Ea) and you will have the final kinetic energy, then ( v = (2K/mass)^(1/2) )

0 comments:

Post a Comment